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(2.6.3ai source code only); 2.6.3 for USA http://www.ifi.uio.no/pgp/ (2.6.3 U.S. Compliant version for
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| 10.
| Chapter 6 Residues and Poles
... f (z)= (z à z 0) m þ (z) þ (z) þ (z 0) 6 =0 Res z=z 0 f (z)= þ (z 0)ifm=1 (mà1) ! þ m à 1 (z 0) ifm>1 (f (z) f (z)= z 2 +9 z+1 = (zà 3i)(z+3i) z+1 ⇒ Res (f, 3 i)= (z+3i) z+1 | 3i = 6i 3i+1 = 6 3ài Res (f, à3i)= (zà ...
xlab.cn.nctu.edu.tw/modules/tinyd1/content/9501/2006complex/ComplexCh6.pdf (0)
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